![]() Repeat step 3 k times to complete all rotations.Īfter all the rotations, return the element at the nth index, which is now the actual position. Replace the first element with the temporary variable. Shift all elements one step to the right. Store the last element in a temporary variable. ![]() To implement rotation, we can use the following approach − Perform the rotations on the array by shifting the elements k times to the right. The actual position can be found by taking the modulo of n and k. Given an array of elements and a number of rotations k, the task is to find the element at a given index n after the rotations.įirst, determine the actual position of the element after k rotations. This program will demonstrate the use of the modulo operator and will be a valuable tool for anyone looking to perform array rotations in JavaScript. In conclusion, we will be developing a simple and efficient program to find the element at a given index after a number of rotations. The element at the final index will be returned as the result of the program. The new index will be found by adding the number of rotations to the original index and then taking the modulo of the sum with the length of the array. We will then perform the rotations by using the modulo operator to find the new index after each rotation. ![]() In the program, we will be taking the input of the array, the number of rotations, and the index. The future continuous tense will be used throughout the explanation. To accomplish this task, we will be using the modulo operator to calculate the new index after each rotation. This program will require us to perform rotations on an array and then return the element present at the specified index. We will be implementing a JavaScript program to find an element at a given index after a number of rotations.
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